#include<bits/stdc++.h>
using namespace std;
using Int = long long;
template<typename T1,typename T2> inline void chmin(T1 &a,T2 b){if(a>b) a=b;}
template<typename T1,typename T2> inline void chmax(T1 &a,T2 b){if(a<b) a=b;}

Int MOD = 1000000007;
template<typename T>
struct Mint{
  T v;
  Mint():v(0){}
  Mint(signed v):v(v){}
  Mint(long long t){v=t%MOD;if(v<0) v+=MOD;}

  Mint pow(long long k){
    Mint res(1),tmp(v);
    while(k){
      if(k&1) res*=tmp;
      tmp*=tmp;
      k>>=1;
    }
    return res;
  }
  
  Mint inv(){return pow(MOD-2);}
  
  Mint& operator+=(Mint a){v+=a.v;if(v>=MOD)v-=MOD;return *this;}
  Mint& operator-=(Mint a){v+=MOD-a.v;if(v>=MOD)v-=MOD;return *this;}
  Mint& operator*=(Mint a){v=1LL*v*a.v%MOD;return *this;}
  Mint& operator/=(Mint a){return (*this)*=a.inv();}
  
  Mint operator+(Mint a) const{return Mint(v)+=a;};
  Mint operator-(Mint a) const{return Mint(v)-=a;};
  Mint operator*(Mint a) const{return Mint(v)*=a;};
  Mint operator/(Mint a) const{return Mint(v)/=a;};

  Mint operator-(){return v?MOD-v:v;}

  bool operator==(const Mint a)const{return v==a.v;}
  bool operator!=(const Mint a)const{return v!=a.v;}
  bool operator <(const Mint a)const{return v <a.v;}

  // find x s.t. a^x = b
  static T log(Mint a,Mint b){
    static T sq = 500000;
    static map<Mint, T> dp;
    if(dp.empty()){
      Mint res(1);
      for(int r=0;r<sq;r++){
        if(!dp.count(res)) dp[res]=r;
        res*=a;
      }
    }
    static Mint p=a.inv().pow(sq);
    Mint res=b;
    for(int q=0;q<=MOD/sq+1;q++){
      if(dp.count(res)){
        T idx=q*sq+dp[res];
        if(idx>0) return idx;
      }
      res*=p;
    }    
    return T(-1);
  }
};
//INSERT ABOVE HERE
signed main(){
  using M = Mint<int>;
  int r;
  cin>>MOD>>r;
  M R(r);
  int q;
  cin>>q;
  for(int i=0;i<q;i++){
    int a,b,c;
    cin>>a>>b>>c;      
    M A(a),B(b),C(c);
    M D=(A.inv()*B*M(2).inv()).pow(2)-A.inv()*C;
    M E=-A.inv()*B*M(2).inv();
    if(D.v==0){
      cout<<E.v<<endl;
      continue;
    }
    int k=M::log(R,D);
    if(k&1){
      cout<<-1<<endl;
      continue;
    }
    M F=R.pow(k/2);      
    int x=(E+F).v,y=(E-F).v;
    if(x>y) swap(x,y);
    cout<<x<<" "<<y<<endl;
  }
  return 0;
}