#include using namespace std; typedef signed long long ll; #undef _P #define _P(...) (void)printf(__VA_ARGS__) #define FOR(x,to) for(x=0;x<(to);x++) #define FORR(x,arr) for(auto& x:arr) #define ITR(x,c) for(__typeof(c.begin()) x=c.begin();x!=c.end();x++) #define ALL(a) (a.begin()),(a.end()) #define ZERO(a) memset(a,0,sizeof(a)) #define MINUS(a) memset(a,0xff,sizeof(a)) //------------------------------------------------------- int N,M,P; int V[101010]; ll S[101010]; ll mo=1000000007; ll comb(ll N_, ll C_) { const int NUM_=400001; static ll fact[NUM_+1],factr[NUM_+1],inv[NUM_+1]; if (fact[0]==0) { inv[1]=fact[0]=factr[0]=1; for (int i=2;i<=NUM_;++i) inv[i] = inv[mo % i] * (mo - mo / i) % mo; for (int i=1;i<=NUM_;++i) fact[i]=fact[i-1]*i%mo, factr[i]=factr[i-1]*inv[i]%mo; } if(C_<0 || C_>N_) return 0; return factr[C_]*fact[N_]%mo*factr[N_-C_]%mo; } ll modpow(ll a, ll n = mo-2) { ll r=1;a%=mo; while(n) r=r*((n%2)?a:1)%mo,a=a*a%mo,n>>=1; return r; } void solve() { int i,j,k,l,r,x,y; string s; cin>>N>>M>>P; FOR(i,N) cin>>V[i]; sort(V,V+N); reverse(V,V+N); FOR(i,100004) S[i+1]=(S[i]+V[i])%mo; ll ret=0; // all for(i=0;i<=M-1;i++) { ret += S[N]*modpow(100-P,N)%mo*modpow(P,i)%mo*comb(i+N-1,i)%mo*modpow(modpow(100),N+i)%mo; } // fail for(i=0;i