#pragma GCC optimize("O3")
#pragma GCC target("avx")
#include <bits/stdc++.h>
#define show(x) std::cerr << #x << " = " << (x) << std::endl
using ll = long long;
constexpr ll MOD = 100000007;
template <ll mod = MOD>
class ModCombination
{
public:
    ModCombination(const std::size_t n) : fact(n + 1, 1), inv(n + 1, 1), inv_fact(n + 1, 1)
    {
        for (ll i = 2; i <= (ll)n; i++) { fact[i] = (fact[i - 1] * i) % mod, inv[i] = ((mod - (mod / i)) * inv[mod % i]) % mod, inv_fact[i] = (inv_fact[i - 1] * inv[i]) % mod; }
    }
    ll combination(const std::size_t n, const std::size_t k) const { return (((fact[n] * inv_fact[k]) % mod) * inv_fact[n - k]) % mod; }

private:
    std::vector<ll> fact, inv, inv_fact;
};
int main()
{
    std::cin.tie(0);
    std::ios::sync_with_stdio(false);
    int H, W, K;
    std::cin >> H >> W >> K;
    ModCombination<> mod(H + W);
    std::vector<int> a(K + 2), b(K + 2);
    a[0] = b[0] = 0, a[K + 1] = H, b[K + 1] = W;
    for (int i = 1; i <= K; i++) { std::cin >> a[i] >> b[i]; }
    std::vector<std::vector<ll>> d(K + 2, std::vector<ll>(K + 2, 0));
    for (int i = 0; i < K + 2; i++) {
        for (int j = 0; j < K + 2; j++) {
            if (a[i] <= a[j] and b[i] <= b[j]) { d[i][j] = mod.combination(a[j] + b[j] - a[i] - b[i], a[j] - a[i]); }
        }
    }
    std::vector<std::vector<ll>> memo1(K + 2, std::vector<ll>(K + 2, -1));
    auto dp1 = [&](auto&& self, const int s, const int g) -> ll {
        if (memo1[s][g] != -1) { return memo1[s][g]; }
        ll ans = d[s][g];
        for (int i = 1; i <= K; i++) {
            if (i == s or i == g or d[i][g] == 0) { continue; }
            const ll minus = self(self, s, i) * d[i][g] % MOD;
            (ans += (MOD - minus)) %= MOD;
        }
        return memo1[s][g] = ans;
    };
    std::vector<ll> memo2(K + 2, -1);
    for (int q = 0; q < (1 << K); q++) {
        auto at = [&](const int j) -> bool { return (q >> j) & 1; };
        std::fill(memo2.begin(), memo2.end(), -1);
        auto dp2 = [&](auto&& self, const int s) {
            if (memo2[s] != -1) { return memo2[s]; }
            ll ans = dp1(dp1, s, K + 1);
            for (int i = 1; i <= K; i++) {
                if (s == i or d[s][i] == 0 or at(i - 1)) { continue; }
                (ans += dp1(dp1, s, i) * self(self, i) % MOD) %= MOD;
            }
            return memo2[s] = ans;
        };
        std::cout << dp2(dp2, 0) << "\n";
    }
    return 0;
}