#include using namespace std; typedef signed long long ll; #undef _P #define _P(...) (void)printf(__VA_ARGS__) #define FOR(x,to) for(x=0;x<(to);x++) #define FORR(x,arr) for(auto& x:arr) #define ITR(x,c) for(__typeof(c.begin()) x=c.begin();x!=c.end();x++) #define ALL(a) (a.begin()),(a.end()) #define ZERO(a) memset(a,0,sizeof(a)) #define MINUS(a) memset(a,0xff,sizeof(a)) //------------------------------------------------------- int N; ll mo=1000000007; ll dp[6030][3030]; void solve() { int i,j,k,l,r,x,y; string s; cin>>N; ll re[3030]={}; for(i=1;i<=N;i++) { dp[N-i][i]=1; re[i]=1; } int shift=0; FOR(i,N-1) { /* ll re[3030]={}; for(x=1;x<=N;x++) { for(y=0;y1;x--) { (re[x]+=sum)%=mo; (sum+=mo-re[x-1])%=mo; } // shift for(x=1;x<=N;x++) { (dp[shift+1][x]+=dp[shift][x])%=mo; (re[x]+=dp[shift][x])%=mo; } for(r=2;r<=N;r++) { (dp[shift+1][r-1]+=dp[shift][r])%=mo; (re[r-1]+=dp[shift][r])%=mo; } for(x=1;x<=N;x++) (re[x]+=mo-dp[shift][x])%=mo; shift++; } ll ret=0; FOR(x,N+1) FOR(y,N+1) ret+=dp[shift+x][y]; cout<