#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#undef _P
#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<(to);x++)
#define FORR(x,arr) for(auto& x:arr)
#define ITR(x,c) for(__typeof(c.begin()) x=c.begin();x!=c.end();x++)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
//-------------------------------------------------------


int N,K;
string A[101];
int B[101];
vector<string> S;
unordered_set<ll> memo[101];
ll mo[2]={1000000007,1000000021};


void dfs(int id,string& cur,string& M,ll H1,ll H2,ll ma,int la=-1) {
	if(S.size()>K+800) {
		return;
		if(cur<S.begin()->substr(0,cur.size())) return;
	}
	
	ll H3=((H1<<32)|H2)^ma;
	
	if(memo[id].count(H3)) return;
	memo[id].insert(H3);
	
	if(id==N) {
		S.push_back(cur);
		return;
	}
	
	
	
	int i;
	FOR(i,N) if(M[i]=='0') {
		if(i&&A[i]==A[i-1]&&M[i-1]=='0') continue;
		M[i]='1';
		cur+=A[i];
		ll G1,G2;
		if(B[i]<10) {
			G1=H1*10+B[i];
			G2=H2*10+B[i];
		}
		else {
			G1=H1*100+B[i];
			G2=H2*100+B[i];
		}
		
		dfs(id+1,cur,M,G1%mo[0],G2%mo[1],ma^(1LL<<(i%50)),i);
		cur.resize(cur.size()-A[i].size());
		M[i]='0';
	}
}


void solve() {
	int i,j,k,l,r,x,y; string s;
	
	cin>>N>>K;
	FOR(i,N) cin>>A[i];
	FOR(i,N) {
		FOR(j,N-1) {
			if(A[j]+A[j+1]<A[j+1]+A[j]||(A[j]+A[j+1]==A[j+1]+A[j]&&A[j]<A[j+1])) {
				swap(A[j],A[j+1]);
			}
		}
	}
	
	string M,C;
	FOR(i,N) {
		M+='0';
		FORR(c,A[i]) B[i]=B[i]*10+c-'0';
	}
	dfs(0,C,M,0,0,0);
	
	sort(ALL(S));
	while(K && S.size()) {
		cout<<S.back()<<endl;
		S.pop_back();
		K--;
	}
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false), cin.tie(0);
	FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	cout.tie(0); solve(); return 0;
}