#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #define REP(i,s,n) for(int i=(int)(s);i<(int)(n);i++) using namespace std; typedef long long int ll; typedef vector VI; typedef pair PI; const double EPS=1e-9; const int N = 30; string s[30]; int first[N][N] = {0}; int dp[N][N] = {0}; int dx[4] = {1,0,-1,0}, dy[4] = {0, 1, 0, -1}; void ff(int x, int y) { if (s[x][y] != '.') { return; } first[x][y] = 1; REP (i, 0, 4) { if (first[x + dx[i]][y + dy[i]] == 0) { ff(x + dx[i], y + dy[i]); } } } int main(void){ int w,h; cin >> w >> h; int x = -1,y; REP(i, 0, h) { cin >> s[i]; REP(j, 0, w) { if (x == -1 && s[i][j] == '.') { x = i, y = j; } } fill_n(dp[i], w, -1); } ff(x, y); queue > que; REP(i,0, h) { REP(j, 0, w) { if (first[i][j]) { que.push(pair(PI(i, j), 0)); } } } int mi = 1000000; while (! que.empty()) { pair pi = que.front(); que.pop(); PI p = pi.first; if (dp[p.first][p.second] >= 0) { continue; } dp[p.first][p.second] = pi.second; if (s[p.first][p.second] == '.' && pi.second) { mi = min(mi, pi.second); } REP(i, 0, 4) { int nx = p.first + dx[i], ny = p.second + dy[i]; int nv = pi.second + 1; que.push(pair(PI(nx,ny), nv)); } } cout << mi - 1 << endl; }