import sequtils,strutils,math,tables
proc toCountSeq[T](x:seq[T]) : seq[tuple[k:T,v:int]] = toSeq(x.toCountTable().pairs)

proc getFactors(n:int):seq[int]=
  const INF = int.high div 4
  proc powerWhenTooBig(x,n:int,modulo:int = 0): int =
    proc mul(x,n,modulo:int):int =
      if n == 0: return 0
      if n == 1: return x
      result = mul(x,n div 2,modulo) mod modulo
      result = (result * 2) mod modulo
      result = (result + x * (n mod 2 == 1).int) mod modulo
      if n == 0: return 1
    if n == 1: return x
    let
      pow_2 = powerWhenTooBig(x,n div 2,modulo)
      odd = if n mod 2 == 1: x else: 1
    if modulo > 0:
      const maybig = int.high.float.sqrt.int div 2
      if pow_2 > maybig or odd > maybig:
        result = mul(pow_2,pow_2,modulo)
        result = mul(result,odd,modulo)
      else:
        result = (pow_2 * pow_2) mod modulo
        result = (result * odd) mod modulo
    else:
      return pow_2 * pow_2 * odd
  proc millerRabinIsPrime(n:int):bool = # O(log n)
    proc ctz(n:int):int{.importC: "__builtin_ctzll", noDecl .} # 01<0000> -> 4
    proc power(x,n:int,modulo:int = 0): int =
      if n == 0: return 1
      if n == 1: return x
      let pow_2 = power(x,n div 2,modulo)
      result = pow_2 * pow_2 * (if n mod 2 == 1: x else: 1)
      if modulo > 0: result = result mod modulo
    if n <= 1 : return false
    if n div 2 == 0: return false
    if n == 2 or n == 3 or n == 5: return true
    let
      s = ctz(n - 1)
      d = (n - 1) div (1 shl s)
    var a_list = @[2, 7, 61]
    if n >= 4_759_123_141 and n < 341_550_071_728_321:
      a_list = @[2, 3, 5, 7, 11, 13, 17]
    if n in a_list : return true
    for a in a_list:
      if powerWhenTooBig(a,d,n) == 1 : continue
      let notPrime = toSeq(0..<s).allIt(powerWhenTooBig(a,d*(1 shl it),n) != n-1)
      if notPrime : return false
    return true
  proc squareFormFactor(n:int):int =
    if millerRabinIsPrime(n) : return n
    proc check(k:int):int =
      proc √(x:int):int = x.float.sqrt.int
      if n <= 1 : return n
      if n mod 2 == 0 : return 2
      if √(n) * √(n) == n : return √(n)
      var P,Q = newSeq[int]()
      block:
        P &= √(k * n)
        Q &= 1
        Q &= k * n - P[0]*P[0]
      while √(Q[^1]) * √(Q[^1]) != Q[^1]:
        let b = (√(k * n) + P[^1] ) div Q[^1]
        P &= b * Q[^1] - P[^1]
        Q &= Q[^2] + b * (P[^2] - P[^1])
      block:
        if Q[^1] == 0 : return check(k + 1)
        let
          b = (√(k * n) - P[^1] ) div Q[^1]
          P0 = b * √(Q[^1]) + P[^1]
          Q0 = √(Q[^1])
          Q1 = (k*n - P0*P0) div Q0
        (P,Q) = (@[P0], @[ Q0, Q1 ])
      while true:
        let b = (√(k * n) + P[^1] ) div Q[^1]
        P &= b * Q[^1] - P[^1]
        Q &= Q[^2] + b * (P[^2] - P[^1])
        if P[^1] == P[^2] or Q[^1] == Q[^2]: break
      let f = gcd(n,P[^1])
      if f != 1 and f != n : return f
      else: return check(k+1)
    return check(1)
  if n == 1 : return @[1]
  if n == 0 : return @[0]
  result = @[]
  var m = n
  while true:
    let p = m.squareFormFactor()
    if p.millerRabinIsPrime(): result &= p
    else: result &= p.getFactors()
    if p == m: return
    m = m div p

let x = stdin.readLine().parseInt()
let factors = x.getFactors().toCountSeq()
var ans = 1
for f in factors:
  if f.v mod 2 == 0 : continue
  ans *= f.k
echo ans