import sequtils template `max=`*(x,y) = x = max(x,y) template `min=`*(x,y) = x = min(x,y) proc getchar_unlocked():char {. importc:"getchar_unlocked",header: "" .} proc scan(): int = while true: let k = getchar_unlocked() if k < '0': break result = 10 * result + k.ord - '0'.ord # 14C2 * 12C2 * 10C2 * 8C2 * 6C2 * 4C2 * 2C2 # 高々:1*6*15*28*45*66*91 なので全て列挙 proc solve(A:seq[int]):int = if A.len == 2: return A[0] xor A[1] for x in 0..