{.checks: off, optimization: speed.} import sequtils,strutils,algorithm import heapqueue proc getchar_unlocked():char {. importc:"getchar_unlocked",header: "" .} proc scan(): int = while true: let k = getchar_unlocked() if k < '0': break result = 10 * result + k.ord - '0'.ord template times*(n:int,body) = (for _ in 0.. Oasis(v *= 2,once) # N <= 200, V <= 500, Lxy <= 9 # x:N * y:N * use:2 => V # 最短でゴール or 最短でオアシス +最短でゴールのみ let n = scan() let v = scan() let ox = scan() - 1 let oy = scan() - 1 var L = newSeqWith(n,newSeqUninitialized[int](n)) for y in 0.. y.v) proc twoFactorDijkestra(sx,sy,sv:int,checkOasis:bool = true):void = var closed = newSeqWith(n,newSeq[bool](n)) var opens = newHeapQueue[field]() opens.push((sx,sy,sv)) while opens.len() > 0: let (x,y,v) = opens.pop() if closed[x][y] : continue closed[x][y] = true if checkOasis and x == ox and y == oy: twoFactorDijkestra(x,y,v * 2,false) continue for d in dxdy4: let (nx,ny) = (d.x + x,d.y + y) if nx < 0 or ny < 0 or nx >= n or ny >= n : continue var n_v = v - L[nx][ny] if n_v <= 0 : continue if not closed[nx][ny]: opens.push((nx,ny,n_v)) if nx == n-1 and ny == n-1: quit "YES",0 twoFactorDijkestra(0,0,v) echo "NO"