#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #define all(c) c.begin(), c.end() #define rall(c) c.rbegin(), c.rend() #define debug(x) cerr << #x << ": " << x << endl using namespace std; typedef long long ll; typedef pair Pll; typedef pair Pii; const ll MOD = 1000000007; const long double EPS = 1e-10; const int dyx[4][2] = { { 0, 1}, {-1, 0}, {0,-1}, {1, 0} }; map memomodpow; ll modpow(ll a, ll t) { if(memomodpow[t]) return memomodpow[t]; ll ret = 1LL; while(t) { if(t & 1) { ret *= a; ret %= MOD; } a *= a; a %= MOD; t >>= 1; } memomodpow[t] = ret; return ret; } map memo; ll solve(ll ei) { if(memo[ei]) return memo[ei]; if(ei <= 8) { ll ret = 0LL; for(int i=1;i<=ei;++i) { ret = ret * 10 + 3; } memo[ei] = ret; } else { ll l = solve(ei/2); ll r = solve((ei+1)/2); memo[ei] = ((l*modpow(10LL, (ei+1)/2))%MOD+r) % MOD; } return memo[ei]; } int main() { ll ei; cin >> ei; if(ei <= 8) { cout << '1' + string(ei, '3') + "\n"; } else { cout << (modpow(10LL, ei) + solve(ei))%MOD << "\n"; } }