#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #define INF_MIN 100000000 #define INF 1145141919 #define INF_MAX 2147483647 #define LL_MAX 9223372036854775807 #define EPS 1e-10 #define PI acos(-1) #define LL long long using namespace std; #define MAX_W 101 #define MAX_H 101 int W, H; int maze[MAX_H][MAX_W]; int dp[MAX_W][MAX_H][15][15]; void init(int x, int y){ for(int i = 0; i < 15; i++){ for(int j = 0; j < 15; j++){ dp[y][x][i][j] = INF; } } } typedef pair P; int dx[] = {1, -1, 0, 0}; int dy[] = {0, 0, 1, -1}; bool checkKado(int a, int b, int c){ return max(a, max(b,c)) == b || min(a, min(b,c)) == b; } int solve(){ dp[0][0][10][maze[0][0]] = 0; queue

PosQue; queue

KadoQue; PosQue.push(P(0, 0)); KadoQue.push(P(10, maze[0][0])); while(PosQue.size()){ P pos = PosQue.front(); P kado = KadoQue.front(); PosQue.pop(); KadoQue.pop(); int x = pos.first, y = pos.second; int a = kado.first, b = kado.second; if(x == W-1 && y == H-1) return dp[y][x][a][b]; for(int i = 0; i < 4; i++){ int nx = x + dx[i]; int ny = y + dy[i]; if(0 <= nx && nx < W && 0 <= ny && ny < H){ int nextKado = maze[ny][nx]; if(a != b && b != nextKado && nextKado != a && (dp[y][x][a][b] == 0 || checkKado(a, b, nextKado)) && dp[ny][nx][b][nextKado] > dp[y][x][a][b] + 1){ //printf("(%d, %d) := %d %d %d\n", nx, ny, a, b, nextKado); dp[ny][nx][b][nextKado] = dp[y][x][a][b] + 1; PosQue.push(P(nx, ny)); KadoQue.push(P(b, nextKado)); } } } } return -1; } int main(){ cin >> W >> H; for(int i = 0; i < H; i++){ for(int j = 0; j < W; j++){ cin >> maze[i][j]; init(j, i); } } cout << solve() << endl; return 0; }