#include #define rep(i, n) for (int i = 0; i < (n); i++) #define rep2(i, a, b) for (int i = (a); i < (b); i++) using namespace std; typedef long long ll; const ll inf = 1e9; const ll mod = 1e9 + 7; int dp[1001][1001]; int levenshteinDisntace(string s, string t) { rep (i, s.length() + 1) { dp[i][0] = i; } rep (i, t.length() + 1) { dp[0][i] = i; } rep2 (i, 1, s.length() + 1) { rep2 (j, 1, t.length() + 1) { int cost; if (s[i] == t[j]) { cost = 0; } else { cost = 1; } dp[i][j] = min({dp[i - 1][j] + 1, dp[i][j - 1] + 1, dp[i - 1][j - 1] + cost}); } } return dp[s.length()][t.length()]; } int main() { int n, m; string s, t; cin >> n >> m >> s >> t; cout << levenshteinDisntace(s, t) << endl; }