#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define REP(i,a,n) for(int i=(a); i<(int)(n); i++) #define rep(i,n) REP(i,0,n) #define FOR(it,c) for(__typeof((c).begin()) it=(c).begin(); it!=(c).end(); ++it) #define ALLOF(c) (c).begin(), (c).end() typedef long long ll; #define MAX 1000000000 int solve(const string& S, const string& T){ std::vector< std::vector > D(S.length()+1, std::vector(T.length()+1, MAX)); rep(i,S.length()+1) D[i][0] = i; rep(i,T.length()+1) D[0][i] = i; REP(i,1,S.length()+1){ REP(j,1,T.length()+1){ int op_nop = MAX; if(S[i-1] == T[j-1]){ op_nop = D[i-1][j-1]; } int op_ins = MAX; if(D[i][j-1] != MAX){ op_ins = D[i][j-1] + 1; } int op_del = MAX; if(D[i-1][j] != MAX){ op_del = D[i-1][j] + 1; } int op_rep = MAX; if(D[i-1][j-1] != MAX){ op_rep = D[i-1][j-1] + 1; } D[i][j] = min(D[i][j], op_nop); D[i][j] = min(D[i][j], op_ins); D[i][j] = min(D[i][j], op_del); D[i][j] = min(D[i][j], op_rep); } } return D[S.length()][T.length()]; } int main(){ int n, m; string S, T; cin >> n >> m; cin >> S; cin >> T; cout << solve(S, T) << endl; return 0; }