#include #include #include #include #include #include #include #include #include #include #include #include #define mk make_pair #define pb push_back using namespace std; typedef long long int ll; typedef pair pos; const ll MOD = 1234567, N = 2010, dx[4] = { -1,1,0,0 }, dy[4] = { 0,0,-1,1 }, MIN = -72340172838, MAX = 72340172838; ll mn(ll a, ll b) { if (a == -1)return b; if (b == -1)return a; return min(a, b); } static ll gcd(ll v1, ll v2) { if (v1 == 0)return v2; if (v2 == 0)return v1; if (v2 > v1)return gcd(v2%v1, v1); return gcd(v1%v2, v2); } ll pw(ll v1, ll v2) { ll v3 = 1; while (v2 > 0) { if (v2 % 2)v3 = (v3*v1) % MOD; v1 = (v1*v1) % MOD; v2 /= 2; } return v3; } ll n,dp[N][N],n2; pos g[N]; int main() { cin >> n; for (int i = 1; i <= n; i++) { cin >> g[i].second >> g[i].first; g[i].first *= -1; } sort(g + 1, g + n + 1); n2 = n - (n / 3); memset(dp, -1, sizeof(dp)); dp[1][0] = 0; for (int i = 1; i <= n; i++) { for (int j = 0; j <= n2; j++) { dp[i + 1][j] = mn(dp[i + 1][j], dp[i][j]); if (j + 1 <= n2 && dp[i][j] != -1)dp[i + 1][j + 1] = mn(dp[i + 1][j + 1], dp[i][j] + g[i].second - g[i].first*j); } } cout << dp[n + 1][n2] << endl; return 0; } /* static int x; void InitA(int T, int X) { x = X; } int GameA(int I, int J) { gcd(1, 2); if (I - 1 >= 1)return -1; if (I + 1 <= 4)return -2; if (J - 1 >= 1)return -3; if (J + 1 <= 4)return -4; } void InitB(int T) { return; } int GameB(int I, int J) { gcd(1, 2); return x; if (I - 1 >= 1)return -1; if (I + 1 <= 4)return -2; if (J - 1 >= 1)return -3; if (J + 1 <= 4)return -4; } */