#include using namespace std; #define rep(i, n) for (int i = 0; i < n; ++i) typedef long long ll; const ll mod = 1e9 + 7; template void add(T &a, T b) {a = (a + b) % mod;} ll solve(string S, int P){ ll dp[200005][2][3][2][P]; rep(i, 200005) rep(j, 2) rep(k, 3) rep(l, 2) rep(m, P) dp[i][j][k][l][m] = 0; dp[0][0][0][0][0] = 1; rep(i, S.size()) rep(j, 2) rep(k, 3) rep(l, 2) rep(m, P) { int x = j ? 9 : S[i] - '0'; rep(d, x + 1) { add(dp[i + 1][j || d < x][(k + d) % 3][l || d == 3][(10 * m + d) % P], dp[i][j][k][l][m]); } } ll ans = 0; rep(j, 2) rep(k, 3) rep(l, 2) rep(m, P){ if((k == 0 || l) && (m != 0)) add(ans, dp[S.size()][j][k][l][m]); } return ans; } int main(){ string A, B; int P; cin >> A >> B >> P; int a = A[A.size() - 1] - '0'; A = A.substr(0, A.size() - 1); A += ('0' + a - 1); ll ans = solve(B, P); add(ans, -solve(A, P) + mod); cout << ans << endl; return 0; }