#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #define int long long using namespace std; #define rep(i, n) for(int i=0;i<(n);++i) typedef pair pii; const int INF = 1l << 60; #define u_b upper_bound #define l_b lower_bound const int MAX_ROW = 610; const int MAX_COL = 610; struct BitMatrix { int n, m; bitset val[MAX_ROW]; BitMatrix(int n = 1, int m = 1) : n(n), m(m) {} inline bitset &operator[](int i) { return val[i]; } }; int linear_equation(BitMatrix A, vector b) { int rank = 0; rep(i, A.n)A[i][A.m] = b[i]; rep(i, A.m) { int pivot = -1; for (int j = rank; j < A.n; ++j) { if (A[j][i]) { pivot = j; break; } } if (pivot != -1) { swap(A[pivot], A[rank]); rep(j, A.n)if (j != rank && A[j][i])A[j] ^= A[rank]; ++rank; } } for (int i = rank; i < A.n; ++i)if (A[i][A.m])return -1; return rank; } //const int mod = //998244353; const int mod = 1000000007; const int FacN = 0;//使わないなら0 constexpr int power(int a, int b) { int res = 1; while (b) { if (b & 1)res *= a; a *= a; res %= mod; a %= mod; b /= 2; } return res; } constexpr int inv(int x) { return power(x, mod - 2); } const struct Fac { int val[FacN]; constexpr Fac() : val() { if (FacN == 0)return; val[0] = 1; for (int i = 1; i < FacN; ++i) val[i] = val[i - 1] * i % mod; } const int &operator[](size_t i) const { return val[i]; } } fac; const struct FacInv { int val[FacN]; constexpr FacInv() : val() { if (FacN == 0)return; val[FacN - 1] = 1; for (int i = 1; i < FacN; ++i)val[FacN - 1] = val[FacN - 1] * i % mod; val[FacN - 1] = inv(val[FacN - 1]); for (int i = FacN - 1; i >= 1; --i)val[i - 1] = val[i] * i % mod; } const int &operator[](size_t i) const { return val[i]; } } fac_inv; int Perm(int n, int r) { if (n < r) return 0; return fac[n] * fac_inv[n - r] % mod; } int Comb(int n, int r) { return Perm(n, r) * fac_inv[r] % mod; } //mod,Factorial書き換え //要検証 const int DIGIT = 35; signed main() { int N, M, X; cin >> N >> M >> X; vector a(N); rep(i, N) cin >> a[i]; BitMatrix A(DIGIT + M, N); vector b(DIGIT + M); rep(d, DIGIT) { rep(i, N) { if (a[i] & (1ll << d))A[d][i] = 1; } if (X & (1ll << d))b[d] = 1; } for (int d = 0; d < M; ++d) { int type, l, r; cin >> type >> l >> r; --l, --r; for (int i = l; i <= r; ++i)A[d + DIGIT][i] = 1; b[d + DIGIT] = type; } int rank = linear_equation(A, b); if (rank == -1)cout << 0 << endl; else cout << power(2, N - rank) << endl; return 0; }