#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #define REP(i,s,n) for(int i=(int)(s);i<(int)(n);i++) using namespace std; typedef long long int ll; typedef vector VI; typedef pair PI; const double EPS=1e-9; const ll mod = 1e9 + 7; const int N = 600; ll b2memo[N][N] = {}; ll b2(int n, int k) { ll &ret = b2memo[n][k]; if (ret >= 0) { return ret; } if (n == 0 && k == 0) { return ret = 1; } if (n < k) { return ret = 0; } ll sub = k == 0 ? 0 : b2(n - 1, k - 1); sub += k * b2(n - 1, k); sub %= mod; return ret = sub; } ll cmemo[N][N]; ll comb(int n, int k) { ll &ret = cmemo[n][k]; if (ret >= 0) { return ret; } if (n == 0 && k == 0) { return ret = 1; } if (n < k) { return ret = 0; } ll sub = k == 0 ? 0 : comb(n - 1, k - 1); sub += comb(n - 1, k); sub %= mod; return ret = sub; } ll powmod(ll a, ll e) { ll sum = 1; ll cur = a; while (e > 0) { if (e % 2) { sum = sum * cur % mod; } cur = cur * cur % mod; e /= 2; } return sum; } int main(void){ int n; cin >> n; ll s = 0; memset(b2memo, -1, sizeof(b2memo)); memset(cmemo, -1, sizeof(cmemo)); REP(k, 1, n + 1) { int q = k * (k - 1); REP(l, k, n + 1) { ll sub = powmod(q, n - l); sub = sub * b2(l, k) % mod; sub = sub * comb(n, l) % mod; s = (s + sub) % mod; } } cout << s << endl; }