#include <iostream>
#include <string>
#include <algorithm>
#include <vector>
#include <stack>
#include <queue>
#include <list>
#include <set>
#include <map>
#include <numeric>
#include <regex>
#include <tuple>
#include<iomanip>
using namespace std;

typedef long long ll;
typedef pair<int, int> P;
#define MOD 1000000007 // 10^9 + 7
#define INF 1000000000 // 10^9
#define LLINF 1LL<<60


int v[101], w[101];
int dp[101][100001]; // dp[i][j] : i個目までの商品で価値jを作るときの最小の重さ


int main() {
	cin.tie(0);
	ios::sync_with_stdio(false);

	int N; cin >> N;
	for (int i = 1; i <= N; i++) cin >> v[i] >> w[i];
	int V; cin >> V;

	for (int i = 0; i <= N; i++) {
		for (int j = 0; j <= 100000;j++) dp[i][j] = INF;
	}
	
	

	dp[0][0] = 0;
	for (int i = 0; i < N; i++) {
		for (int j = 0; j <= 100000; j++) {
			if (j + v[i + 1] <= 100000) dp[i + 1][j + v[i + 1]] = min(dp[i + 1][j + v[i + 1]], dp[i][j] + w[i + 1]);
			dp[i + 1][j] = min(dp[i + 1][j], dp[i][j]);
		}
	}

	int ansmin = dp[N][V];
	
	// dp[N][V+1]～dp[N][100000]までの最小値を求める
	int ans = INF;
	for (int j = V + 1; j <= 100000; j++) {
		ans = min(ans, dp[N][j]);
	}
	
	if (ansmin == 0) cout << 1 << endl;
	else cout << ansmin << endl;


	if (ans < INF) cout << ans - 1 << endl;
	else cout << "inf" << endl;


	return 0;
}