#include #define rep(i, n) for (int i = 0; i < (n); i++) #define rep2(i, a, b) for (int i = (a); i < (b); i++) #define rrep(i, n) for (int i = (n) - 1; i >= 0; i--) #define rrep2(i, a, b) for (int i = (a) - 1; i >= (b); i--) #define all(v) (v).begin(), (v).end() using namespace std; typedef long long ll; const ll inf = 1e9; const ll mod = 1e9 + 7; int N; ll G[1000], D[1000]; pair EXP[1000]; int main() { cin >> N; rep (i, N) cin >> G[i] >> D[i]; rep (i, N) EXP[i] = make_pair(G[i] - 30000 * D[i], i + 1); sort(EXP, EXP + N); ll sum = EXP[N - 1].first * 6; if (sum >= 100 * 30000) { cout << "YES" << endl; rep (i, 6) cout << EXP[N - 1].second << endl; } else { cout << "NO" << endl; } }