#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#undef _P
#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<(to);x++)
#define FORR(x,arr) for(auto& x:arr)
#define ITR(x,c) for(__typeof(c.begin()) x=c.begin();x!=c.end();x++)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
//-------------------------------------------------------

ll N,K;
ll mo=1000000007;
const int NUM_=400001;
static ll fact[NUM_+1],factr[NUM_+1],inv[NUM_+1];


void solve() {
	int i,j,k,l,r,x,y; string s;
	
	cin>>N>>K;
	inv[1]=fact[0]=factr[0]=1;
	for (int i=2;i<=NUM_;++i) inv[i] = inv[mo % i] * (mo - mo / i) % mo;
	for (int i=1;i<=NUM_;++i) fact[i]=fact[i-1]*i%mo, factr[i]=factr[i-1]*inv[i]%mo;
	
	ll ret=0;
	// iが登場しない
	if(N>K) ret+=N*(N+1)/2%mo*fact[N-1]%mo*factr[N-1-K]%mo;
	// iの後にi+1がある
	if(K>=2) ret+=N*(N-1)/2%mo*fact[N-2]%mo*factr[K-2]%mo*factr[N-K]%mo*fact[K]%mo*((mo+1)/2);
	cout<<ret%mo<<endl;
	
	
	
	
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false), cin.tie(0);
	FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	cout.tie(0); solve(); return 0;
}