#include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; using lint = long long; using ld = long double; using pint = pair; using plint = pair; #define MOD 1000000007LL #define INF 1000000000LL #define EPS 1e-10 #define FOR(i,n,m) for(lint i=n;i<(int)m;i++) #define REP(i,n) FOR(i,0,n) #define DUMP(a) REP(d,a.size()){cout<> tree; lint ans = 0; #define MAX_N 1000000 long long extgcd(long long a, long long b, long long& x, long long& y) { long long d = a; if (b != 0) { d = extgcd(b, a % b, y, x); y -= (a / b) * x; } else { x = 1; y = 0; } return d; } long long mod_inverse(long long a, long long m) { long long x, y; if(extgcd(a, m, x, y) == 1) return (m + x % m) % m; else return -1; } vector fact(MAX_N+1, INF); long long mod_fact(long long n, long long& e) { if(fact[0] == INF) { fact[0]=1; if(MAX_N != 0) fact[1]=1; for(lint i = 2; i <= MAX_N; ++i) { fact[i] = (fact[i-1] * i) % MOD; } } e = 0; if(n == 0) return 1; long long res = mod_fact(n / MOD, e); e += n / MOD; if((n / MOD) % 2 != 0) return (res * (MOD - fact[n % MOD])) % MOD; return (res * fact[n % MOD]) % MOD; } // return nCk long long mod_comb(long long n, long long k) { if(n < 0 || k < 0 || n < k) return 0; long long e1, e2, e3; long long a1 = mod_fact(n, e1), a2 = mod_fact(k, e2), a3 = mod_fact(n - k, e3); if(e1 > e2 + e3) return 0; return (a1 * mod_inverse((a2 * a3) % MOD, MOD)) % MOD; } lint _pow(lint a, lint n) { if(n == 0) return 1; else { lint res = 1; lint buf = a; while(n > 0) { if(n % 2 == 1) { res *= buf; res %= MOD; } buf *= buf; buf %= MOD; n/=2; } return res; } } lint factoria[202020]; void dfs(int pos, int par, int height) { ans += factoria[n] * _pow(height, MOD - 2); ans %= MOD; REP(i, tree[pos].size()) { if(tree[pos][i] == par) continue; dfs(tree[pos][i], pos, height + 1); } return; } int main() { ios::sync_with_stdio(false); cin.tie(0); factoria[0] = 1; FOR(i, 1, 202020) { factoria[i] = factoria[i - 1] * i; } cin >> n; tree.resize(n); REP(i, n - 1) { int u, v; cin >> u >> v; u--; v--; tree[u].pb(v); tree[v].pb(u); } dfs(0, -1, 1); cout << ans << endl; return 0; } /* --------------------------------------- */