//1<=x<=2^N(xは2^Mの倍数)                                                       
//を満たすxの個数

#include<iostream>
#include<cmath>

using namespace std;

int main(){

    long long N,M,twoN,twoM;

    cin>>N>>M;

    twoN=pow(2,N);
    twoM=pow(2,M);

    cout<<twoN/twoM<<endl;
}