// yukicoder: No.747 循環小数N桁目 Hard
// 2019.5.6 bal4u

#include <stdio.h>

#if 1
#define gc() getchar_unlocked()
#define pc(c) putchar_unlocked(c)
#else
#define gc() getchar()
#define pc(c) putchar(c)
#endif

int inN() { // 長い数字列 % 6
	int n = 0, c = gc();
	do n = (10 * n + (c & 0xf)) % 6, c = gc(); while (c >= '0');
	return n;
}

int inK() { // 長い数字列の最後の桁
	int p, c;
	if ((p = gc()) == '0') return 0; 
	while (1) {
		c = gc();
		if (c < '0') break;
		p = c;
	}
	return p;
}

char ans[6] = "428571";
int a[6][2] = {{0,0},{1,1},{4,2},{3,3},{4,4},{1,5}};

int main()
{
	int N, K, p = 1;

	// Nの入力と処理
	N = inN();
	
	// Kの入力と処理
	K = inK();
	if (K == 0) goto Done;
	p = a[N][K & 1];
	
Done:
	pc(ans[p]), pc('\n');
	return 0;
}