// yukicoder: No.237 作図可能性
// 2019.5.11

#include <stdio.h>

#define MAX 1000000000
// #define FLEN 5
// int fermat[] = { 3, 5, 17, 257, 65537 };
int fn[] = { 1,3,5,15,17,51,85,255,257,771,1285,3855,4369,
  13107,21845,65535,65537,196611,327685,983055,1114129,3342387,
  5570645,16711935,16843009,50529027,84215045,252645135,
286331153,858993459, MAX+1 };
#define PLEN 31
int p2[35];

int bsch(int x) {
	int m, l = 0, r = PLEN;
    while (l < r) {
        m = (l+r) >> 1;
        if (p2[m] <= x) l = m + 1; else r = m;
    }
	if (l == 0) return 1;
	return l;
}

int main()
{
	int i, A, ans;
	
	for (i = 0; i < PLEN; i++) p2[i] = 1<<i;
	scanf("%d", &A);
	ans = 0; for (i = 0; fn[i] <= A; i++) ans += bsch(A/fn[i]);
	printf("%d\n", ans-2);
	return 0;
}