#include <iostream>
using namespace std;
typedef long long LL;
int main(int argc, char* argv[])
{
	LL l,r;
	int n;
	cin>>l>>r>>n;
	LL num0=(r-l+1)/n;
	LL Num=num0*n;
	for (int i=0;i<n;i++){	
		if (Num+i<=r){
			cout<<num0+i<<endl;
		}else{
			cout<<num0<<endl;
		}
	}
	return 0;
}