#include #define rep(i, n) for (int i = 0; i < int(n); i++) #define rrep(i, n) for (int i = int(n) - 1; i >= 0; i--) #define reps(i, n) for (int i = 1; i <= int(n); i++) #define rreps(i, n) for (int i = int(n); i >= 1; i--) #define repc(i, n) for (int i = 0; i <= int(n); i++) #define rrepc(i, n) for (int i = int(n); i >= 0; i--) #define repi(i, a, b) for (int i = int(a); i < int(b); i++) #define repic(i, a, b) for (int i = int(a); i <= int(b); i++) #define each(x, y) for (auto &x : y) #define all(a) (a).begin(), (a).end() #define bit(b) (1ll << (b)) #define uniq(v) (v).erase(unique(all(v)), (v).end()) using namespace std; using i32 = int; using i64 = long long; using f80 = long double; using vi32 = vector; using vi64 = vector; using vf80 = vector; using vstr = vector; inline void yes() { cout << "Yes" << '\n'; exit(0); } inline void no() { cout << "No" << '\n'; exit(0); } inline i64 gcd(i64 a, i64 b) { if (min(a, b) == 0) return max(a, b); if (a % b == 0) return b; return gcd(b, a % b); } inline i64 lcm(i64 a, i64 b) { return a / gcd(a, b) * b; } void solve(); int main() { ios::sync_with_stdio(0); cin.tie(0); cout << fixed << setprecision(16); solve(); return 0; } template class pqasc : public priority_queue, greater> {}; template class pqdesc : public priority_queue, less> {}; template inline void amax(T &x, T y) { if (x < y) x = y; } template inline void amin(T &x, T y) { if (x > y) x = y; } template inline T power(T x, i64 n, T e = 1) { T r = e; while (n > 0) { if (n & 1) r *= x; x *= x; n >>= 1; } return r; } template istream& operator>>(istream &is, vector &v) { for (auto &x : v) is >> x; return is; } template ostream& operator<<(ostream &os, const vector &v) { rep(i, v.size()) { if (i) os << ' '; os << v[i]; } return os; } void solve() { int n; cin >> n; vi64 y(n); cin >> y; sort(all(y)); if (y[0] == y[n - 1]) { cout << 1 << '\n'; return; } int li = 0, ri = (n + 1) / 2; i64 ltotal = 0, rtotal = 0; reps(i, n - 1) { rtotal += abs(y[ri] - y[i]); } i64 ans = ltotal + rtotal; repic(i, 1, n - 2) { ltotal += y[i] - y[li]; rtotal -= y[ri] - y[i]; int ll = i / 2, rr = (n - i - 2) / 2 + i + 1; if (li < ll && y[li] < y[ll]) { ltotal += (i64) (li + ll - i) * (y[ll] - y[li]); } if (ri < rr && y[ri] < y[rr]) { rtotal += (i64) (ri + rr - i - n) * (y[rr] - y[ri]); } li = ll; ri = rr; amin(ans, ltotal + rtotal); } cout << ans << '\n'; }