#include #define rep(i, n) for (int i = 0; i < int(n); i++) #define rrep(i, n) for (int i = int(n) - 1; i >= 0; i--) #define reps(i, n) for (int i = 1; i <= int(n); i++) #define rreps(i, n) for (int i = int(n); i >= 1; i--) #define repc(i, n) for (int i = 0; i <= int(n); i++) #define rrepc(i, n) for (int i = int(n); i >= 0; i--) #define repi(i, a, b) for (int i = int(a); i < int(b); i++) #define repic(i, a, b) for (int i = int(a); i <= int(b); i++) #define each(x, y) for (auto &x : y) #define all(a) (a).begin(), (a).end() #define bit(b) (1ll << (b)) #define uniq(v) (v).erase(unique(all(v)), (v).end()) using namespace std; using i32 = int; using i64 = long long; using f80 = long double; using vi32 = vector; using vi64 = vector; using vf80 = vector; using vstr = vector; inline void yes() { cout << "Yes" << '\n'; exit(0); } inline void no() { cout << "No" << '\n'; exit(0); } inline i64 gcd(i64 a, i64 b) { if (min(a, b) == 0) return max(a, b); if (a % b == 0) return b; return gcd(b, a % b); } inline i64 lcm(i64 a, i64 b) { return a / gcd(a, b) * b; } void solve(); int main() { ios::sync_with_stdio(0); cin.tie(0); cout << fixed << setprecision(16); solve(); return 0; } template class pqasc : public priority_queue, greater> {}; template class pqdesc : public priority_queue, less> {}; template inline void amax(T &x, T y) { if (x < y) x = y; } template inline void amin(T &x, T y) { if (x > y) x = y; } template inline T power(T x, i64 n, T e = 1) { T r = e; while (n > 0) { if (n & 1) r *= x; x *= x; n >>= 1; } return r; } template istream& operator>>(istream &is, vector &v) { for (auto &x : v) is >> x; return is; } template ostream& operator<<(ostream &os, const vector &v) { rep(i, v.size()) { if (i) os << ' '; os << v[i]; } return os; } void solve() { int n; cin >> n; if (n == 2) { cout << 1 << " " << 2 << '\n'; cout << 3 << " " << 4 << '\n'; return; } vector ans(n, vi32(n)); bool rev = false; rep(i, n / 2) { int x, y = i; if (rev) x = n - 1; else x = 0; int w = n / 2 - 1; reps(j, 2 * n) { ans[y][x] = j + i * n * 2; if (j == 2 * n) break; y = y < n / 2 ? y + n / 2 : y - n / 2; if (!rev) { x = (x + w) % n; while (ans[y][x] > 0) x = (x + 1) % n; } else { x = (x - w + n) % n; while (ans[y][x] > 0) x = (x - 1 + n) % n; } } if (!rev && x < n / 2 || rev && x >= n / 2) rev = !rev; } rep(i, n) cout << ans[i] << '\n'; }