#include <bits/stdc++.h>
using namespace std;
using ll = long long;
#define fi first
#define se second
#define pb push_back
#define all(v) (v).begin(),(v).end()
ll mod = 1000000007;
ll INF = 1000000099;
//cin.tie(0);
//ios::sync_with_stdio(false);


signed main(){
    ll n,m,nk=0,sk=0,ans=INF;
    cin>>n>>m;
    ll cnt[n+10];//index i番目の完答数
    vector<pair<ll,ll>> f(n),s(n);

    for(int i=0;i < n;i++)
    {
        cin>>cnt[i];
        cnt[i]++;
        cin>>f.at(i).fi>>s.at(i).fi;
        f.at(i).se=i;
        s.at(i).se=i;
        if(cnt[i]>=3){
            sk++;
            nk++;
        }else if(cnt[i]>=2){
            nk++;
        }
    }
    sort(f.begin(),f.end());
    sort(s.begin(),s.end());

    ll l=0,r=n;
    if(nk>=m)ans=min(ans,sk);

    for(int l=0;l <= n;l++)
    {
        if(l>0){
            cnt[f.at(l-1).se]--;
            if(cnt[f.at(l-1).se]==2){
                sk--;
            }else if(cnt[f.at(l-1).se]==1){
                nk--;
            }

            if(l<n && f.at(l-1).fi==f.at(l).fi){
                continue;
            }
        }
        while(m>nk || (r<n-1 && -1<r &&s.at(r).fi==s.at(r+1).fi)){
            if(r>-1) r--;
            else break;

            if(r<n-1){
                cnt[s.at(r+1).se]++;
                if(cnt[s.at(r+1).se]==3){
                    sk++;
                }else if(cnt[s.at(r+1).se]==2){
                    nk++;
                }
            }
            //if(r<10)cout << l<<" "<<r << endl;
        }
        //if(ans<40080 && ans>sk)cout << ans << endl;
        if(m<=nk)ans=min(ans,sk);
    }
    
    cout << ans << endl;
}