def make_prime_numbers(n):
    '''
    n以下の素数を列挙したリストを出力する
    計算量：O(NloglogN)
    入出力例：30 -> [2, 3, 5, 7, 11, 13, 17, 19, 23, 29]
    '''

    is_prime = [True]*(n+1)
    is_prime[0] = False
    is_prime[1] = False
    for i in range(2, int(n**0.5) + 1):
        if not is_prime[i]:
            continue
        for j in range(2 * i, n + 1, i):
            is_prime[j] = False
    prime_numbers = [i for i in range(n + 1) if is_prime[i]]
    return prime_numbers
  
def solve(a, b):
    res = (a + b)**0.5
    return res == int(res)

n = int(input())
prime_list = make_prime_numbers(n)
memo = {}
for i in prime_list:
    memo[i] = 1
print(len(prime_list))

cnt = 0
for r in range(len(prime_list)):
    if prime_list[r] **2 > 2 * prime_list[-1]:
        break
    for p in range(len(prime_list)):
        q = prime_list[r]**2 - prime_list[p]
        if q < 0:
            break
        if q in memo :
            cnt += 1

print(cnt)