#include<iostream>
#include<vector>
#include<string>
#include<cmath>
#include<algorithm>
#include<functional>
#include<numeric>
#include<queue>
#include<stack>
#include<map>
#include<unordered_map>
#include<set>
#include<bitset>
#include<random>
#pragma region
using namespace std;
#define FOR(i,r,n) for(ll i = (ll)(r); i < (ll)(n); i++)
#define rep(i,n) FOR(i,0LL,n)
#define RFOR(i,r,n) for(ll i=(ll)(n-1);i>=r;i--)
#define rrep(i,n) RFOR(i,0LL,n)
#define all(x) x.begin(),x.end()
#define rall(x) x.rbegin(),x.rend()
#define COUNT(a,y,x) upper_bound(all(a), y) - lower_bound(all(a), x)
#define UNIQUE(a) sort(all(a)); a.erase(unique(all(a)), a.end())
#define pb push_back
typedef long long int ll;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef pair<ll, ll> pll;
typedef vector<pll> vpll;
typedef vector<string> vs;
typedef map<ll, ll> MAP;
const ll inf = 1LL << 61;
const ll mod = 1000000007LL;
//const ll mod = 998244353LL;

ll n = 0, m = 0, ans = 0, tmp = 0, ma = -inf, mi = inf;
string s;
ll dx[9] = { 0,1,0,-1,0,1,1,-1,-1 }, dy[9] = { 0,0,1,0,-1,1,-1,1,-1 };
#define endl '\n'
#pragma endregion
#define MAX 222222


ll sum[MAX / 2][333], a[MAX];
vll pr;
bool is[MAX + 1];

void AllPrime(ll x) {
  rep(i, x + 1) is[i] = true;
  is[0] = false;
  is[1] = false;
  rep(i, x + 1) {
    if (is[i]) {
      pr.pb(i);
      for (ll j = 2 * i; j <= x; j += i) is[j] = false;
    }
  }
}


int main(void) {
  ios::sync_with_stdio(false); cin.tie(0);



  AllPrime(2000);
  unordered_map<ll, ll> idx;
  cin >> n;
  FOR(i, 1, n + 1) cin >> a[i];
  rep(i, pr.size()) idx[pr[i]] = i;
  FOR(i, 1, n + 1) {
    tmp = a[i];
    rep(j, pr.size()) {
      ll cnt = 0;
      while (tmp%pr[j] == 0) {
        cnt++;
        tmp /= pr[j];
      }
      sum[i][j] += cnt;
    }
  }
  FOR(i,1, n+1) {
    rep(j, pr.size()) {
      sum[i][j] += sum[i - 1][j];
    }
  }
  cin >> m;
  while (m--) {
    ll p, le, ri;
    cin >> p >> le >> ri;
    bool ok = true;
    rep(i, pr.size()) {
      ll cnt = 0;
      while (p%pr[i] == 0) {
        cnt++;
        p /= pr[i];
      }
      if (sum[ri][i] - sum[le - 1][i] < cnt) ok = false;
    }

    if (ok&&p == 1) cout << "Yes" << endl;
    else cout << "NO" << endl;
  }


  return 0;
}