#include using namespace std; //repetition #define FOR(i,a,b) for(ll i=(a);i<(b);++i) #define rep(i, n) for(ll i = 0; i < (ll)(n); i++) //container util #define all(x) (x).begin(),(x).end() //typedef typedef long long ll; typedef vector VI; typedef vector VVI; typedef vector VLL; typedef vector VVLL; typedef vector VS; typedef pair PII; typedef pair PLL; //const value //const ll MOD = 1e9 + 7; //const int dx[] = {0,1,0,-1};//{0,0,1,1,1,-1,-1,-1}; //const int dy[] = {1,0,-1,0};//{1,-1,0,1,-1,0,1,-1}; //conversion inline int toInt(string s) {int v; istringstream sin(s);sin>>v;return v;} inline ll toLL(string s) {ll v; istringstream sin(s);sin>>v;return v;} template inline string toString(T x) {ostringstream sout;sout<> n; VLL a(n); rep(i,n) cin >> a[i]; ll mul[n][prime.size()]; memset(mul,0,sizeof(mul)); rep(i,n){ if(i != 0){ rep(j,prime.size()){ mul[i][j] = mul[i-1][j]; while(a[i] % prime[j] == 0) mul[i][j]++,a[i]/=prime[j]; } }else{ rep(j,prime.size()){ while(a[i] % prime[j] == 0) mul[i][j]++,a[i]/=prime[j]; } } } ll q; cin >> q; rep(i,q){ ll p,l,r; cin >> p >> l >> r; l--,r--; bool flag = true; rep(j,prime.size()){ int cnt = mul[r][j]; if(l != 0) cnt -= mul[l-1][j]; while(p % prime[j] == 0) cnt--, p/=prime[j]; if(cnt < 0 )flag = false; } if(flag) cout << "Yes" << "\n"; else cout << "NO" << "\n"; } return 0; }