#include <bits/stdc++.h>
using namespace std;
typedef long long ll;

int main() {
    int mod = 1e6+7;
    ll n;
    cin>>n;
    ll up=n/2%mod;
    ll down=(n-n/2)%mod;
    cout << (up*(down+1)%mod+down)%mod << endl;
    return 0;
}