#include <bits/stdc++.h> 

using namespace std;
typedef long long ll;

int v[] = {6, 2, 5, 5, 4, 5, 6, 3, 7, 6};

int main() {
    int N;
    cin >> N;
    if (N % 2 == 0) {
        for (int i = 0; i < N / 2; i++)
            cout << 1;
        cout << endl;
    } else {
        cout << 7;
        for (int i = 0; i < (N - 3) / 2; i++)
            cout << 1;
        cout << endl;
    }
}