#include <bits/stdc++.h>
using namespace std;
using lint = long long;
template<class T = int> using V = vector<T>;
template<class T = int> using VV = V< V<T> >;

struct Edge { int to, cost; };

template<class T, class Edge> V<T> dijkstra(const VV<Edge>& g, int s = 0) {
  V<T> dist(g.size(), numeric_limits<T>::max());
  using P = pair<T, int>;
  priority_queue< P, V<P>, greater<P> > pque;
  pque.emplace(dist[s] = 0, s);
  while (!pque.empty()) {
    T d; int v;
    tie(d, v) = pque.top(); pque.pop();
    if (d > dist[v]) continue;
    for (const auto& e : g[v]) if (dist[v] + e.cost < dist[e.to]) {
      pque.emplace(dist[e.to] = dist[v] + e.cost, e.to);
    } 
  }
  return dist;
}

int main() {
  cin.tie(nullptr); ios::sync_with_stdio(false);
  int h, w; cin >> h >> w;
  int gi, gj; cin >> gi >> gj, --gi, --gj;
  auto in = [&](int i, int j) -> int { return i * w + j; };
  auto out = [&](int i, int j) -> int { return (h + i) * w + j; };
  VV<Edge> g(2 * h * w);
  VV<> a(h, V<>(w));
  for (int i = 0; i < h; ++i) for (int j = 0; j < w; ++j) {
    cin >> a[i][j];
    g[in(i, j)].emplace_back(Edge{out(i, j), a[i][j]});
    for (int di = -1; di <= 1; ++di) for (int dj = -1; dj <= 1; ++dj) if (abs(di) + abs(dj) == 1) {
      int ni = i + di, nj = j + dj;
      if (ni < 0 or ni >= h or nj < 0 or nj >= w) continue;
      g[out(i, j)].emplace_back(Edge{in(ni, nj), 0});
    }
  }

  int q; cin >> q;
  struct Q { int t, i, j, k; };
  V<Q> qs(q);
  for (int t = 0; t < q; ++t) {
    qs[t].t = t;
    cin >> qs[t].i >> qs[t].j >> qs[t].k, --qs[t].i, --qs[t].j;
  }
  sort(begin(qs), end(qs), [](const auto& l, const auto& r) { return l.k < r.k; });

  V<lint> res(q);
  auto itr = begin(qs);
  while (itr != end(qs)) {
    lint k = itr->k;
    if (k >= 2500) {
      for (int i = 0; i < h; ++i) for (int j = 0; j < w; ++j) {
        g[in(i, j)][0].cost = a[i][j] + 2500 * 2500;
      }
      auto d = dijkstra<lint>(g, in(gi, gj));
      while (itr != end(qs)) {
        res[itr->t] = d[out(itr->i, itr->j)] + (abs(itr->i - gi) + abs(itr->j - gj) + 1) * (k * k - 2500 * 2500);
        ++itr;
      }
      break;
    }

    for (int i = 0; i < h; ++i) for (int j = 0; j < w; ++j) {
      g[in(i, j)][0].cost = a[i][j] + k * k;
    }
    auto d = dijkstra<lint>(g, in(gi, gj));
    while (itr != end(qs) and itr->k == k) {
      res[itr->t] = d[out(itr->i, itr->j)];
      ++itr;
    }
  }
  for (lint e : res) cout << e << '\n';
}