#include <iostream>

long long f(long long sum, long long lim) {
  if (lim + lim < sum) return 0;
  long long ma = std::min(sum - 1, lim);
  long long mi = sum - ma;
  return ma - mi + 1;
}

// ab + bc + cd + da   = K
// a(b + d) + c(b + d) = K
// (a + c)(b + d)      = K

int main() {
  long long N, K;
  std::cin >> N >> K;
  long long ans = 0;
  for (long long div = 2; div * div <= K; ++div) {
    if(K % div != 0) continue;
    long long div2 = K / div;
    ans += f(div, N) * f(div2, N) * (div == div2 ? 1 : 2);
  }
  std::cout << ans << std::endl;
}