// 263 Common Palindromes Extra // AOJ 2292 Common Palindromes // 2019.8.16 bal4u #include #include typedef long long ll; #if 1 #define gc() getchar_unlocked() #else #define gc() getchar() #endif int ins(int *f, char *s) // 文字列の入力 スペース以下の文字で入力終了 { char *p = s; int c; do c = gc(), f[c]++, *s++ = c; while (c > ' '); *--s = 0; return s - p; } #define MAX 1000010 //// 回文木の構築 typedef struct { int par, son[30], suffix_link, len, cnt; } NODE; NODE node[MAX]; int sz = 2; int last; char S[MAX]; int W; // 文字列 void init_palindromic_tree() { // 回文木の初期化 node[0].suffix_link = -1, node[0].len = -1; } void add_palindromic_tree(int idx) { // 文字を回文木に追加。文字位置 S[idx] char c = S[idx]; int a = S[idx] - '>'; int t = last; while (1) { if (idx-1-node[t].len >= 0 && S[idx-1-node[t].len] == c) break; t = node[t].suffix_link; } if (node[t].son[a] > 0) { last = node[t].son[a], node[last].cnt++; return; } last = sz++; node[t].son[a] = last; node[last].len = node[t].len + 2, node[last].par = t, node[last].cnt = 1; if (node[last].len == 1) node[last].suffix_link = 1; else while (1) { t = node[t].suffix_link; if (idx-1-node[t].len >= 0 && S[idx-1-node[t].len] == c) { node[last].suffix_link = node[t].son[a]; break; } } } char *ss; int ws; char *tt; int wt; int f[2][MAX]; int as[128], at[128]; int main() { int i, t; ll ans; ws = ins(as, ss = S); S[ws] = '>', S[ws+1] = '@'; wt = ins(at, tt = ss + ws + 2); W = ws + wt + 2; int u, v; t = 0; for (i = 'A'; i <= 'Z'; i++) { if (as[i]) u++; if (at[i]) v++; if (as[i] & at[i]) t = 1; } if (t == 0) { puts("0"); return 0; } if (u == 1 && v == 1 && ws == wt) { printf("%lld\n", (ll)ws*(ws+1)*(2*ws+1)/6); return 0; } init_palindromic_tree(); for (i = 0; i < ws; i++) { add_palindromic_tree(i); f[0][last]++; } add_palindromic_tree(i++), add_palindromic_tree(i++); for ( ; i < W; i++) { add_palindromic_tree(i); f[1][last]++; } ans = 0; for (i = sz-1; i > 1; i--) { ans += (ll)f[0][i] * f[1][i]; f[0][node[i].suffix_link] += f[0][i]; f[1][node[i].suffix_link] += f[1][i]; } printf("%lld\n",ans); return 0; }