#include<iostream>
using namespace std;
long N,K,ans;
long f(long L)
{
	if(L<=N)return L-1;
	else if(L<=2*N)return 2*N-L+1;
	else return 0;
}
main()
{
	cin>>N>>K;
	for(long i=1;i*i<=K;i++)
	{
		if(K%i==0)
		{
			long now=f(i)*f(K/i);
			ans+=now*(i*i==K?1:2);
		}
	}
	cout<<ans<<endl;
}