#include #define rep(i, a) for (int i = 0; i < (a); i++) #define rep2(i, a, b) for (int i = (a); i < (b); i++) using namespace std; typedef long long ll; const ll inf = 1e9; const ll mod = 1e9 + 7; int C, N; int dp[101][100001]; int a[100]; int solve() { rep (i, 101) rep (j, C + 1) dp[i][j] = inf; dp[0][0] = 0; rep (i, N) { rep (j, C + 1) { dp[i + 1][j] = min(dp[i + 1][j], dp[i][j]); if (j + a[i] <= C) { dp[i + 1][j + a[i]] = min(dp[i + 1][j + a[i]], dp[i + 1][j] + 1); } } } return dp[N][C]; } int main() { cin >> C >> N; rep (i, N) cin >> a[i]; int ans = solve(); if (ans == inf) ans = -1; cout << ans << endl; }