#pragma GCC optimize ("Ofast")
#pragma GCC optimize ("unroll-loops")
#pragma GCC target ("avx")

#include <cassert>
#include <cmath>
#include <cstdint>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
#include <bitset>
#include <complex>
#include <deque>
#include <iostream>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <sstream>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>

using namespace std;

using Int = long long;

template <class T1, class T2> ostream &operator<<(ostream &os, const pair<T1, T2> &a) { return os << "(" << a.first << ", " << a.second << ")"; };
template <class T> void pv(T a, T b) { for (T i = a; i != b; ++i) cerr << *i << " "; cerr << endl; }
template <class T> void chmin(T &t, const T &f) { if (t > f) t = f; }
template <class T> void chmax(T &t, const T &f) { if (t < f) t = f; }

constexpr int MAX_L = 590;
constexpr int MAX_N = 300005;

bitset<MAX_N> dp[MAX_L];

int N;
int L;
char ans[MAX_L];

int main() {
  dp[0][0] = 1;
  for (int i = 0; i < MAX_L; ++i) {
    for (int j = 1; i + j < MAX_L; ++j) {
      dp[i + j] |= dp[i] << (j * j);
    }
  }
  
  for (; ~scanf("%d", &N); ) {
    for (L = 0; !dp[L][N]; ++L) {}
cerr<<"L = "<<L<<endl;
    int now = 0;
    int last = 1, level = 0;
    for (int i = 0; i < L; ++i) {
      // check 0
      if (last == 0) {
        const int n = N - now - level * level;
        if (n >= 0 && dp[L - i][n]) {
          ans[i] = '0';
          now += level * level;
          last = 0;
          level = 1;
        } else {
          ans[i] = '1';
          last = 1;
          ++level;
        }
      } else {
        bool ok = false;
        for (int j = i + 1; j <= N; ++j) {
          const int n = N - now - (level + (j - i)) * (level + (j - i));
          ok = ok || (n >= 0 && dp[L - j][n]);
        }
        if (ok) {
          ans[i] = '0';
          last = 0;
          ++level;
        } else {
          ans[i] = '1';
          now += level * level;
          last = 1;
          level = 1;
        }
      }
    }
    ans[L] = '\0';
    puts(ans);
  }
  
  return 0;
}