#include #include using namespace std; #define REP(i,n) for (int i=0;i<(n);i++) #define REP2(i,m,n) for (int i=m;i<(n);i++) typedef long long ll; int N; ll dp[303030]; ll par[303030]; ll par2[303030]; string ans[303030]; void solve() { cin >> N; REP(i, N+1) dp[i] = 1LL << 59; dp[0] = 0; REP(i, N) for (ll j = 1; i + j * j <= N; ++j) { if (dp[i] + j < dp[i + j * j]) { dp[i + j * j] = dp[i] + j; ans[i + j * j] = ans[i]; int last = i == 0 ? 0 : ans[i].back() - '0'; REP(_, j) ans[i + j * j] += to_string(last), last ^= 1; } else if (dp[i] + j == dp[i + j * j]) { string tmp = ans[i]; int last = i == 0 ? 0 : ans[i].back() - '0'; REP(_, j) tmp += to_string(last), last ^= 1; ans[i + j * j] = min(ans[i + j * j], tmp); } } cout << ans[N] << "\n"; } int main() { cin.tie(0); ios::sync_with_stdio(false); solve(); }