#include #include #include #include #include #include #include #include #include #include static const int MOD = 1000000007; using ll = long long; using u32 = uint32_t; using namespace std; template constexpr T INF = ::numeric_limits::max()/32*15+208; template struct SegmentTree{ using T = typename M::T; int sz; vector seg; explicit SegmentTree(int n) { sz = 1; while(sz < n) sz <<= 1; seg.assign(2*sz, M::e()); } void set(int k, const T &x){ seg[k + sz] = x; } void build(){ for (int i = sz-1; i > 0; --i) seg[i] = M::f(seg[2*i], seg[2*i+1]); } void update(int k, const T &x){ k += sz; seg[k] = x; while (k >>= 1) seg[k] = M::f(seg[2*k], seg[2*k+1]); } T query(int a, int b){ T l = M::e(), r = M::e(); for(a += sz, b += sz; a < b; a >>=1, b>>=1){ if(a & 1) l = M::f(l, seg[a++]); if(b & 1) r = M::f(seg[--b], r); } return M::f(l, r); } template int find(int t, C &c, T &val, int k, int l, int r){ if(r-l == 1){ val = f(val, seg[k]); return c(val) ? k-sz : -1; } int m = (l+r) >> 1; if(m <= t) return find(t, c, val, (k << 1) | 1, m, r); if(t <= l && !c(val = f(val, seg[k]))) return -1; int lv = find(t, c, val, (k << 1) | 0 , l, m); if(~lv) return lv; return find(t, c, val, (k << 1) | 1, m, r); } template int find(int t, C &c){ T val = M::e(); return find(t, c, val, 1, 0, sz); } T operator[](const int &k) const { return seg[k + sz]; } }; struct Monoid{ using T = pair; static T f(T a, T b) { return {a.first+b.first, a.second+b.second}; } static T e() { return {0, 0}; } }; int main() { int n, q; cin >> n >> q; vector ans(q); vector> v(n); for (int i = 0; i < n; ++i) { scanf("%d", &v[i].first); v[i].second = i; } v.emplace_back(-INF, -1); sort(v.begin(),v.end(), greater<>()); vector> query(q); int tmp = 0; for (int i = 0; i < q; ++i) { scanf("%d %lld %lld %lld",&tmp, &query[i][1], &query[i][2], &query[i][0]); query[i][3] = i; } sort(query.begin(),query.end(), greater<>()); int cur = 0; SegmentTree seg(n); for (auto &&p : query) { while(v[cur].first >= p[0]) { seg.update(v[cur].second, {v[cur].first, 1}); cur++; } auto res = seg.query(p[1]-1, p[2]); ans[p[3]] = res.first-(ll)res.second*p[0]; } for (int i = 0; i < q; ++i) { printf("%lld\n", ans[i]); } return 0; }