#include #include #include #include #include #define _USE_MATH_DEFINES #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define FOR(i,m,n) for(int i=(m);i<(n);++i) #define REP(i,n) FOR(i,0,n) #define ALL(v) (v).begin(),(v).end() const int INF = 0x3f3f3f3f; const long long LINF = 0x3f3f3f3f3f3f3f3fLL; const double EPS = 1e-8; const int MOD = 1000000007; // 998244353; const int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1}; /*-------------------------------------------------*/ void solve(int len, char c, string &ans) { while (len--) { ans += c; if (c == '0') { c = '1'; } else { c = '0'; } } } int main() { cin.tie(0); ios::sync_with_stdio(false); // freopen("input.txt", "r", stdin); int n; cin >> n; vector dp(n + 1, INF), prev0(n + 1, -1), prev1(n + 1, -1); dp[0] = 0; FOR(i, 1, n + 1) { for (int j = 1; j * j <= i; ++j) { int score = dp[i - j * j] + j; if (score < dp[i]) { dp[i] = score; prev0[i] = prev1[i] = j; } else if (score == dp[i]) { if (prev0[i] % 2 == 0) prev0[i] = j; if (prev1[i] % 2 == 1) prev1[i] = j; } } } string ans = "0"; int now = n; while (now > 0) { if (ans.back() == '0') { solve(prev0[now], '0', ans); now -= prev0[now] * prev0[now]; } else { solve(prev1[now], '1', ans); now -= prev1[now] * prev1[now]; } } ans.erase(ans.begin()); cout << ans << '\n'; return 0; }