#include <bits/stdc++.h>
using namespace std;

// as + bt = GCD(a,b) a,b:const s,t:var(any)
// return GCD(a,b)
long long extGCD(long long a, long long b, long long& s,
                 long long& t) {
  s = 1, t = 0;
  while(b) {
    long long tmp = a / b;
    a -= b * tmp;
    s -= t * tmp;
    swap(a, b);
    swap(s, t);
  }
  return a;
}

// x≡b_i(mod m_i) calc min x,lcm(m_i). if not exist, return
// (-1,-1)
pair<long long, long long> ChineseRem(
    const vector<long long>& b,
    const vector<long long>& m) {
  long long r = 0, lcm = 1;
  assert(b.size() == m.size());
  long long bsize = b.size();
  for(int i = 0; i < bsize; ++i) {
    long long p, q, d, now;
    d = extGCD(lcm, m[i], p, q);
    if((b[i] - r) % d != 0) return make_pair(-1, -1);
    now = (b[i] - r) / d * p % (m[i] / d);
    r += lcm * now;
    lcm *= m[i] / d;
  }
  return make_pair((r + lcm) % lcm, lcm);
}

bool ch = 0;
vector<long long> x, y;

int main() {
  x.resize(3);
  y.resize(3);
  for(int i = 0; i < 3; ++i) {
    cin >> x[i] >> y[i];
    if(y[i]) ch = 1;
  }
  pair<long long, long long> ans = ChineseRem(x, y);
  if(!ch)
    cout << ans.second << endl;
  else
    cout << ans.first << endl;
  return 0;
}