#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; typedef long long ll; typedef unsigned int ui; const ll mod = 1000000007; const ll INF = (ll)1000000007 * 1000000007; typedef pair P; #define stop char nyaa;cin>>nyaa; #define rep(i,n) for(int i=0;i=0;i--) #define Rep(i,sta,n) for(int i=sta;i=sta;i--) #define rep1(i,n) for(int i=1;i<=n;i++) #define per1(i,n) for(int i=n;i>=1;i--) #define Rep1(i,sta,n) for(int i=sta;i<=n;i++) typedef long double ld; typedef complex Point; const ld eps = 1e-8; const ld pi = acos(-1.0); typedef pair LP; int n; ll a,b; typedef vector< vector< ll > > mat; typedef vector< ll > vec; mat mtmul(mat &A, mat &B){ mat C(A.size(), vec(B[0].size())); rep(i, (int)A.size()) { rep(k, (int)B.size()) { rep(j, (int)B[0].size()) { C[i][j] = (C[i][j] + (A[i][k] * B[k][j]) ) ; C[i][j]%=mod; } } } return C; } mat mtpow(mat A, ll n) { mat B(A.size(), vec(A.size())); rep(i, (int)A.size()) { B[i][i] = 1; } while (n > 0) { if (n&(ll)1)B = mtmul(B, A); A = mtmul(A, A); n >>= 1; } return B; } void solve(){ cin >> a >> b >> n; mat A={{a,b}, {1,0}}; A=mtpow(A,n-1); mat a={{1},{0}}; ll ans=mtmul(A,a)[0][0]; cout << ans << endl; } int main(){ ios::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(50); solve(); }