/*
    No.820 Power of Two
    https://yukicoder.me/problems/no/820
*/
#include <bits/stdc++.h>
using namespace std;

int main() {
    ios::sync_with_stdio(0);
    cin.tie(0);
    long long int n, k;
    cin >> n >> k;

    // cout << "(2^n 2^k) = (" << pow(2, n) << ", " << pow(2, k) << endl;
    cout << (long)(pow(2, n) / pow(2, k)) << endl;

    return 0;
}