def check(n) :
    return abs(n) <= 99999999

def f(n) :
    n = abs(n)
    s = str(n)
    c = s.count('0')
    l = len(s)
    if c == l-1 and c >= 2 :
        return True
    else :
        return False

a,b = map(int,input().split())

if f(a) and f(b) :
    print(a*b//10)
elif check(a*b) :
    print(a*b)
else :
    print("E")