#include <bits/stdc++.h>
#define LLI long long int
#define FOR(v, a, b) for(LLI v = (a); v < (b); ++v)
#define FORE(v, a, b) for(LLI v = (a); v <= (b); ++v)
#define REP(v, n) FOR(v, 0, n)
#define REPE(v, n) FORE(v, 0, n)
#define REV(v, a, b) for(LLI v = (a); v >= (b); --v)
#define ALL(x) (x).begin(), (x).end()
#define RALL(x) (x).rbegin(), (x).rend()
#define ITR(it, c) for(auto it = (c).begin(); it != (c).end(); ++it)
#define RITR(it, c) for(auto it = (c).rbegin(); it != (c).rend(); ++it)
#define EXIST(c,x) ((c).find(x) != (c).end())
#define fst first
#define snd second
#define popcount __builtin_popcount
#define UNIQ(v) (v).erase(unique(ALL(v)), (v).end())
#define bit(i) (1LL<<(i))

#ifdef DEBUG
#include <misc/C++/Debug.cpp>
#else
#define dump(...) ((void)0)
#endif

#define gcd __gcd

using namespace std;
template <class T> constexpr T lcm(T m, T n){return m/gcd(m,n)*n;}

template <typename I> void join(ostream &ost, I s, I t, string d=" "){for(auto i=s; i!=t; ++i){if(i!=s)ost<<d; ost<<*i;}ost<<endl;}
template <typename T> istream& operator>>(istream &is, vector<T> &v){for(auto &a : v) is >> a; return is;}

template <typename T, typename U> bool chmin(T &a, const U &b){return (a>b ? a=b, true : false);}
template <typename T, typename U> bool chmax(T &a, const U &b){return (a<b ? a=b, true : false);}
template <typename T, size_t N, typename U> void fill_array(T (&a)[N], const U &v){fill((U*)a, (U*)(a+N), v);}

struct Init{
  Init(){
    cin.tie(0);
    ios::sync_with_stdio(false);
  }
}init;

int main(){
  int N;
  while(cin >> N){
    vector<LLI> X(N), Y(N); cin >> X >> Y;

    vector<LLI> ans(N+2);

    auto f =
      [&](LLI k){
        REP(i,N){
          if(X[i] + Y[i] < k){
            return false;
          }
        }
        
        return true;
      };

    LLI lb = -1, ub = LLONG_MAX / 2;
    while(abs(lb-ub) > 1){
      LLI mid = (lb+ub) / 2;

      if(f(mid)){
        lb = mid;
      }else{
        ub = mid;
      }
    }

    LLI m = lb;

    dump(m);

    ans[0] = 0;
    ans[N+1] = m;

    FORE(i,1,N){
      ans[i] = min(X[i-1], m);
    }
    
    

    cout << m << endl;
    join(cout, ALL(ans), "\n");
  }

  return 0;
}