/** * code generated by JHelper * More info: https://github.com/AlexeyDmitriev/JHelper * @author */ #include #include #ifndef SOLUTION_COMMON_H #include using namespace std; using ll = long long; using PI = pair; template using V = vector; using VI = V; #define _1 first #define _2 second #ifdef MY_DEBUG # define DEBUG(x) x #else # define DEBUG(x) #endif template inline void debug(T &A) { DEBUG( for (const auto &a : A) { cerr << a << " "; } cerr << '\n'; ) } template inline void debug_with_format(T &A, Func f) { DEBUG( for (const auto &a : A) { cerr << f(a) << " "; } cerr << '\n'; ) } template inline void debug_dim2(T &A) { DEBUG( for (const auto &as : A) { debug(as); } ) } template inline void debug(const char *format, Args const &... args) { DEBUG( fprintf(stderr, format, args ...); cerr << '\n'; ) } template string format(const string &fmt, Args ... args) { size_t len = snprintf(nullptr, 0, fmt.c_str(), args ...); vector buf(len + 1); snprintf(&buf[0], len + 1, fmt.c_str(), args ...); return string(&buf[0], &buf[0] + len); } template string fmtP(pair a) { stringstream ss; ss << "(" << a._1 << "," << a._2 << ")"; return ss.str(); } #define SOLUTION_COMMON_H #endif //SOLUTION_COMMON_H const int MOD = 1000000007; class D { public: ll calc(VI &bit, ll l, ll r) { V>> memo(60, V>(2, V(2, -1))); function dfs = [&](int k, int more, int less) { if (k == -1) return 1ll; if (memo[k][more][less] != -1) return memo[k][more][less]; ll res = 0ll; for (int i = 0; i < 2; ++i) { if (!(bit[k] == i || bit[k] == 2)) continue; if (i == 0 && !more && (l >> k & 1)) continue; if (i == 1 && !less && !(r >> k & 1)) continue; int nmore = more || !(l >> k & 1) && i == 1; int nless = less || (r >> k & 1) && i == 0; res += dfs(k - 1, nmore, nless); } memo[k][more][less] = res; return res; }; return dfs(59, 0, 0); } void solve(std::istream& in, std::ostream& out) { int n; ll l, r; in >> n >> l >> r; V a(n); for (int i = 0; i < n; ++i) { in >> a[i]; } VI g(n); int id = 1; auto mergeTpe = [](int t1, int t2) { if (t1 == 2 && t2 == 1 || t1 == 1 && t2 == 2) return -1; if (t1 == 0 || t1 == 1) return t2; return t1; }; VI bit(60); for (int k = 59; k >= 0; --k) { int tpe = 0; // 0: 0000, 1: 1111, 2: 0011, 3: 1100 int cur = 0; int curG = 0; for (int i = 0; i < n; ++i) { // グループが変わった if (i == 0 || curG != g[i]) { tpe = mergeTpe(tpe, cur); if (tpe == -1) { out << 0; return; } cur = (a[i] >> k & 1) == 1 ? 1 : 0; curG = g[i]; continue; } if (cur == 0 && (a[i] >> k & 1) == 1) { debug("enter(2) %d %d", k, i); cur = 2; g[i] = id++; continue; } if (cur == 1 && (a[i] >> k & 1) == 0) { debug("enter(3) %d %d", k, i); cur = 3; g[i] = id++; continue; } if (cur == 2 && (a[i] >> k & 1) == 0) { out << 0; return; } if (cur == 3 && (a[i] >> k & 1) == 1) { out << 0; return; } if (cur == 2 || cur == 3) { g[i] = g[i - 1]; } } tpe = mergeTpe(tpe, cur); if (tpe == -1) { out << 0; return; } if (tpe == 0 || tpe == 1) { bit[k] = 2; } else if (tpe == 2) { bit[k] = 0; } else { bit[k] = 1; } debug(g); } debug(bit); out << calc(bit, l, r); } }; int main() { D solver; std::istream& in(std::cin); std::ostream& out(std::cout); solver.solve(in, out); return 0; }