#include <bits/stdc++.h>
#define whlie while
#define pb push_back
#define eb emplace_back
#define fi first
#define se second
#define rep(i,N) for(int i = 0; i < (N); i++)
#define repr(i,N) for(int i = (N) - 1; i >= 0; i--)
#define rep1(i,N) for(int i = 1; i <= (N) ; i++)
#define repr1(i,N) for(int i = (N) ; i > 0 ; i--)
#define each(x,v) for(auto& x : v)
#define all(v) (v).begin(),(v).end()
#define sz(v) ((int)(v).size())
#define vrep(v,it) for(auto it = v.begin(); it != v.end(); it++)
#define vrepr(v,it) for(auto it = v.rbegin(); it != v.rend(); it++)
#define ini(...) int __VA_ARGS__; in(__VA_ARGS__)
#define inl(...) ll __VA_ARGS__; in(__VA_ARGS__)
#define ins(...) string __VA_ARGS__; in(__VA_ARGS__)
using namespace std; void solve();
using ll = long long; using vl = vector<ll>;
using vi = vector<int>; using vvi = vector< vector<int> >;
constexpr int inf = 1001001001;
constexpr ll infLL = (1LL << 61) - 1;
struct IoSetupNya {IoSetupNya() { cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); cerr << fixed << setprecision(7);} } iosetupnya;
template<typename T, typename U> inline bool amin(T &x, U y) { return (y < x) ? (x = y, true) : false; }
template<typename T, typename U> inline bool amax(T &x, U y) { return (x < y) ? (x = y, true) : false; }
template<typename T, typename U> ostream& operator <<(ostream& os, const pair<T, U> &p) { os << p.first << " " << p.second; return os; }
template<typename T, typename U> istream& operator >>(istream& is, pair<T, U> &p) { is >> p.first >> p.second; return is; }
template<typename T> ostream& operator <<(ostream& os, const vector<T> &v) { int s = (int)v.size(); rep(i,s) os << (i ? " " : "") << v[i]; return os; }
template<typename T> istream& operator >>(istream& is, vector<T> &v) { for(auto &x : v) is >> x; return is; }
void in(){} template <typename T,class... U> void in(T &t,U &...u){ cin >> t; in(u...);}
void out(){cout << "\n";} template <typename T,class... U> void out(const T &t,const U &...u){ cout << t; if(sizeof...(u)) cout << " "; out(u...);}
template<typename T>void die(T x){out(x); exit(0);}
#ifdef NyaanDebug
  #include "NyaanDebug.h"
  #define trc(...) do { cerr << #__VA_ARGS__ << " = "; dbg_out(__VA_ARGS__);} while(0)
  #define trca(v,N) do { cerr << #v << " = "; array_out(v , N);cout << endl;} while(0)
#else
  #define trc(...)
  #define trca(...)
  int main(){solve();}
#endif

using P = pair<int,int>; using vp = vector<P>;
constexpr int MOD = /** 1000000007; //*/ 998244353;
////////////////

template<typename T>
struct LiChaoTree{

  struct Line{
    T slope , intercept;
    Line(T slope,T intercept) : slope(slope),intercept(intercept){}
    inline T get(T x) const{
      return slope * x + intercept;
    }
    inline bool over(const Line& other , const T &x) const{
      return get(x) < other.get(x);
    }
  };

  // remind セグ木は0-indexedの実装
  vector<T> xset;
  vector<Line> seg;
  int _size;

  // 引数xにはソート済みのx座標の集合を入れる
  LiChaoTree(const vector<T> &x, T INF) : xset(x) {
    _size = 1; while(_size < (int)xset.size()) _size <<= 1;
    while( (int)xset.size() < _size) xset.push_back(xset.back() + 1);
    seg.assign(2 * _size - 1, Line(0, INF));
  }

  // y = ax + bなる直線を追加
  void update(T a, T b){ 
    Line x(a , b);
    // x.over(xset[right])とするとout of boundになることに留意する
    int left = 0 , right = _size , seg_idx = 0;
    while(1){
      int mid = (left + right) >> 1;
      bool l_over = x.over(seg[seg_idx], xset[left]);
      bool r_over = x.over(seg[seg_idx], xset[mid]);
      if(r_over) swap(seg[seg_idx], x);
      if(left + 1 >= right) return;
      else if(l_over != r_over) seg_idx = 2 * seg_idx + 1 , right = mid;
      else seg_idx = 2 * seg_idx + 2 , left = mid;
    }
  }

  // x = xset[k]なる点における最小値クエリ
  T query(int k) {
    const T x = xset[k];
    k += _size - 1;
    T ret = seg[k].get(x);
    while(k > 0) {
      k = (k - 1) >> 1;
      ret = min(ret, seg[k].get(x) );
    }
    return ret;
  }

};

void solve(){
  ini(N);
  vl a(N) , x(N) , y(N); in(a , x , y);
  vl dp(N + 1 , 0);
  LiChaoTree<ll> lichao(a , infLL);
  rep(i , N){
    lichao.update(x[i] * (-2) , x[i] * x[i] + y[i] * y[i] + dp[i]);
    dp[i + 1] = lichao.query(i) + a[i] * a[i];
  }
  trc(dp);
  out(dp[N]);
}