#include using namespace std; typedef long long ll; #define P pair #define FOR(I,A,B) for(ll I = ll(A); I < ll(B); ++I) #define FORR(I,A,B) for(ll I = ll((B)-1); I >= ll(A); --I) #define TO(x,t,f) ((x)?(t):(f)) #define SORT(x) (sort(x.begin(),x.end())) // 0 2 2 3 4 5 8 9 #define POSL(x,v) (lower_bound(x.begin(),x.end(),v)-x.begin()) //xi>=v x is sorted #define POSU(x,v) (upper_bound(x.begin(),x.end(),v)-x.begin()) //xi>v x is sorted #define NUM(x,v) (POSU(x,v)-POSL(x,v)) //x is sorted #define REV(x) (reverse(x.begin(),x.end())) //reverse ll gcd(ll a,ll b){if(a%b==0)return b;return gcd(b,a%b);} ll lcm(ll a,ll b){ll c=gcd(a,b);return ((a/c)*(b/c)*c);} #define NEXTP(x) next_permutation(x.begin(),x.end()) const ll INF=ll(1e18)+ll(7); const ll MOD=1000000007LL; #define out(a) cout< rnd(0.00,1.00); int N,M,ans=MOD,sum=0,K,anst=0; vector< vector > A; void dfs(int k=0){ if(k==N)return; FOR(i,0,M){ anst += A[k][i]; if(k==N-1)if(K-anst>=0)ans = min(ans,K-anst); dfs(k+1); anst -= A[k][i]; } } int main(){ cin >> N >> M >> K; vector x(M); A.resize(N,x); FOR(i,0,N)FOR(j,0,M)cin >> A[i][j]; dfs(0); if(ans==MOD)ans = -1; cout << ans << endl; }